Voyage estimate
MR voyage: Lake Charles to Buenos Aires
A MR carrying 37,000 tonnes from Lake Charles to Buenos Aires sails about 6,459 nm laden on the open-sea route, about 21.5 days at 12.5 knots. With the ballast leg back and 4 days in port, the round voyage takes about 46.2 days and burns about 971 tonnes of fuel.
Round voyage
46.2 d
21.5 d laden
Laden distance
6,459 nm
Shortest route
Fuel (VLSFO)
971 t
Round voyage
CO2
3,059 t
Outside EU ETS
Round voyage breakdown
| Leg | Distance | Speed | Days | Fuel |
|---|---|---|---|---|
Laden Lake Charles → Buenos Aires | 6,459 nm | 12.5 kn | 21.5 | 517 t |
Ballast Buenos Aires → Lake Charles | 6,459 nm | 13 kn | 20.7 | 414 t |
Port time Loading and discharge | — | — | 4.0 | 40 t |
| Round voyage | 12,919 nm | 46.2 | 971 t |
Laden on the open-sea route; ballast on the open-sea route.
Emissions and EU ETS
The round voyage burns about 971 tonnes of VLSFO, emitting about 3,059 tonnes of CO2. Neither port is in the EU ETS area, so no EU allowances are needed for this voyage.
Assumptions
- Cargo
- 37,000 t
- Laden speed
- 12.5 kn at 24 t/day
- Ballast speed
- 13 kn at 20 t/day
- Port time
- 4 days at 10 t/day
- Laden draft
- 12 m
- CO2 factor
- 3.151 t per t fuel
Other ship sizes on this route
Questions
How long does a MR take from Lake Charles to Buenos Aires?
About 21 days 13 hours laden at 12.5 knots over 6,459 nm on the open-sea route. The full round voyage, with the ballast leg back and 4 days in port, takes about 46.2 days.
How much fuel does a MR burn on this voyage?
About 971 tonnes of VLSFO for the round voyage (517 t laden, 414 t ballast, 40 t in port), emitting about 3,059 tonnes of CO2.